-16x^2-10x+30=0

Solution for -16x^2-10x+30=0 equation:

-16x^2-10x+30=0

a = -16; b = -10; c = +30;
Δ = b2-4ac
Δ = -102-4·(-16)·30
Δ = 2020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2020}=\sqrt{4*505}=\sqrt{4}*\sqrt{505}=2\sqrt{505}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{505}}{2*-16}=\frac{10-2\sqrt{505}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{505}}{2*-16}=\frac{10+2\sqrt{505}}{-32}
$